Posted by **Sian** on Tuesday, March 26, 2013 at 9:21am.

An elevator with a man inside, of gross mass 500KG, starts moving upwards with a costant acceleration and acquires a velocity os 2m/s after travelling a distance os 3m.Find the pull in the cables during the accelerated motion.

If the elevator, before stopping, moves with a constant deceleration from a constant velocity of 2m/s and comes to rest in 2 second, calculate the force exerted by the man of 75kg mass on the floor on the elevator.

- Collage Physics -
**black_widow**, Tuesday, March 26, 2013 at 9:51am
The pull of cable is 5.24x10^3N

The force exerted by the man =75N

Is it correct?

- Collage Physics -
**bobpursley**, Tuesday, March 26, 2013 at 10:09am
first, find the acceleration.

Vf^2=Vi^2+2ad

4=0+2a*3

a=2/3 m/s^2

then

force= m(g+a)=500(9.8+2/3) =

## Answer This Question

## Related Questions

- Collage Physics - n elevator with a man inside, of gross mass 500KG, starts ...
- engineering physical - An elevator with a man inside, of gross mass 500KG, ...
- dynamics of rigid bodies - 1. An elevator weighing 15 kN starts from rest and ...
- physics - The cavle on an elevator is what pulls the elevator up, and allows it ...
- physics - an elevator and its load have a total mass of 1000 kg. find the ...
- physics - an elevator and its load have a total mass of 1000kg. find the tension...
- Physics - A man measures the acceleration of an elevator using a spring balance...
- Physics - A man measures the acceleration of an elevator using a spring balance...
- physics - In Example 5.8 in the text book, we investigated the apparent weight ...
- physics - A 70kg man stands on a bathroom scale in an elevator. As the elevator ...

More Related Questions