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Collage Physics

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An elevator with a man inside, of gross mass 500KG, starts moving upwards with a costant acceleration and acquires a velocity os 2m/s after travelling a distance os 3m.Find the pull in the cables during the accelerated motion.

If the elevator, before stopping, moves with a constant deceleration from a constant velocity of 2m/s and comes to rest in 2 second, calculate the force exerted by the man of 75kg mass on the floor on the elevator.

  • Collage Physics - ,

    The pull of cable is 5.24x10^3N
    The force exerted by the man =75N
    Is it correct?

  • Collage Physics - ,

    first, find the acceleration.
    Vf^2=Vi^2+2ad

    4=0+2a*3

    a=2/3 m/s^2

    then

    force= m(g+a)=500(9.8+2/3) =

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