I need help with something and can't find this anywhere online. my structure looks like this
OH
CH2
CH3CH2CH2CHCHCH2CH3
CH3
So that OH looks like it is on a ethyl group. I need to write the IUPAC name and I wrote 3-methyl-4-heptanol but realized my mistake as that would indicate OH is on a methyl group. How do I express it as a ethyl group?
...just change the methyl part to ethyl.... 2-ethyl-4-heptanol!
i just realized after entering my question my structure did not stay the way I wanted it to. the CH2 and OH are supposed to be over the 4th carbon in the chain and the CH3 is supposed to be under the 3rd.
Ceasium chloride crystallises as abcc lattice
To correctly express the OH group as being attached to an ethyl group, you need to modify the IUPAC name. Here's how you can do it:
Step 1: Identify the longest carbon chain that includes the OH group. In this case, it is a seven-carbon chain.
Step 2: Number the carbon atoms in the main chain using the lowest possible numbers. Start numbering from the end that gives the OH group the lowest number. In this case, we start numbering from the left end of the chain since that gives the OH group the lower number.
1 2 3 4 5 6 7
OH CH2 CH2 CHCH CH2 CH3
CH3
Step 3: Determine the substituents on the main chain. In this case, there is a methyl group (CH3) attached to carbon 3 and an ethyl group (CH2CH3) attached to carbon 4.
Step 4: Combine the substituents and the parent chain name to construct the IUPAC name. The substituents are listed in alphabetical order. The correct IUPAC name for this molecule is 4-ethyl-3-methylheptan-1-ol.
Note: In the IUPAC name, the position of the substituents is indicated by numbers (lower numbers take priority). The -ol ending indicates an alcohol functional group.
So, in summary, the correct IUPAC name for the given structure is 4-ethyl-3-methylheptan-1-ol.