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March 25, 2017

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A sample of gas with a volume of 14.9 liters at 2.6 atmospheres pressure and a temperature of 25°C is allowed to expand to a volume of 29.3 liters at a temperature of 15°C. What is the final pressure (atm)atof the gas?

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    PV=nRT
    14.9L*2.6atm=n*0.08206*(25+273.15)
    n=1.583mol
    PV=nRT
    P*29.3L=1.583mol*(15+273.15)*0.08206
    P=1.2778atm

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