in a class of 60 students,the number of students who pass biology is 6 more than the number who pass chemistry.every student passed at least one of the two subject.how many pass in only biology.how many pass in only chemistry.

Hard to say. All we know is that if c students pass chemistry only, and x pass both,

c + (c+6) + x = 60
2c = 54-x
c = 27-x
and x>0, so
c<27

So, we could have

26 pass chemistry only,
32 pass biology only,
2 pass both

all the way down to
0 pass chemistry only,
6 pass biology only,
54 pass both

Yes

Let's solve the problem step by step.

Step 1: Assign variables to the unknowns.
Let's assume the number of students who pass chemistry is x.
Therefore, the number of students who pass biology is (x + 6).

Step 2: Set up an equation based on the given information.
We know that every student passed at least one of the two subjects. This means that the total number of students who passed chemistry or biology is 60.

Therefore, we can write the equation:
x + (x + 6) = 60

Step 3: Solve the equation.
Combine like terms:
2x + 6 = 60

Subtract 6 from both sides of the equation:
2x = 60 - 6
2x = 54

Divide both sides of the equation by 2:
x = 54 / 2
x = 27

Step 4: Calculate the number of students who passed in only biology.
Since the number of students who passed biology is (x + 6), we substitute x with 27:
Number of students who passed biology = 27 + 6 = 33

Step 5: Calculate the number of students who passed in only chemistry.
Since we know that 60 students passed in total, and 33 students passed in only biology, we can calculate the number of students who passed in only chemistry.
Number of students who passed in only chemistry = Total number of students - Number of students who passed in only biology
Number of students who passed in only chemistry = 60 - 33 = 27

Therefore, there are 33 students who passed only biology and 27 students who passed only chemistry.

To find the number of students who passed only biology and the number of students who passed only chemistry, we can use a strategy called Venn diagrams.

Let's assume the number of students who passed only biology is 'x' and the number of students who passed only chemistry is 'y'. We can represent these variables in a Venn diagram as follows:

```
Biology
[ ]
/ \
/ \
[ ] \
Chemistry \
[______]
```

Now let's fill in the information we have:

- The number of students who pass biology is 6 more than the number who pass chemistry. So, we can set up an equation: x = y + 6.

- Every student passed at least one of the two subjects. This means that the total number of students who passed biology and the total number of students who passed chemistry should add up to the total number of students in the class. So, we can set up another equation: x + y = 60.

Now we have a system of equations to solve:

x = y + 6 (Equation 1)
x + y = 60 (Equation 2)

We can solve this system of equations by substituting the value of x from Equation 1 into Equation 2:

(y + 6) + y = 60
2y + 6 = 60
2y = 60 - 6
2y = 54
y = 54 / 2
y = 27

Now that we have the value of y, we can substitute it back into Equation 1 to find the value of x:

x = 27 + 6
x = 33

Therefore, the number of students who passed only biology is 33, and the number of students who passed only chemistry is 27.