A car traveling at 150 miles/hour strikes a wall and bounces backwards at 30 miles/hour. If the car is in contact with the wall for 0.1 seconds, what is the force that the car exerts on the driver.

To determine the force that the car exerts on the driver, we need to use Newton's second law of motion, which states that force (F) is equal to mass (m) multiplied by acceleration (a):

F = m * a

In this case, the acceleration can be found by calculating the change in velocity (Δv) divided by the time interval (Δt) during which the car hits the wall and bounces back:

a = Δv / Δt

First, let's calculate the change in velocity. The initial velocity of the car is 150 miles/hour, and after the collision, it bounces backwards at 30 miles/hour. To calculate the change in velocity, we subtract the final velocity from the initial velocity:

Δv = 30 miles/hour - (-150 miles/hour)
= 180 miles/hour

Next, we need to convert the velocity change to the corresponding SI unit, meters per second (m/s), because the SI unit of force is Newtons (N). To convert from miles/hour to m/s, we use the conversion factor:

1 mile/hour = 0.44704 m/s

Therefore, Δv in m/s is:

Δv = 180 miles/hour * 0.44704 m/s / 1 mile/hour
= 80.47 m/s

Now let's calculate the acceleration:

a = Δv / Δt

The time interval given is 0.1 seconds:

a = 80.47 m/s / 0.1 s
= 804.7 m/s²

Now, to calculate the force, we need the mass (m) of the car. Since the mass is not provided, we cannot determine the exact force without this information. The force can be determined by multiplying the mass of the car by the calculated acceleration (F = m * a).

Therefore, without knowing the mass of the car, we cannot determine the force that the car exerts on the driver.