Posted by Anonymous on .
determine the vertical asymptotes of the graph of function.g(x)=x^3 diveded by 5x^3x^222x

college algebra 
Reiny,
b(x) = x^3/(5x^3  x^2  22x)
= x^2/(5x^2  x  22) , after dividing by x , x≠0
f'(x) = (2x(5x^2  x  22)  x^2(10x  1) )/(5x^2x22)^2
to have a vertical tangent, the slope must be undefined, that is
the denominator of the above f'(x) must be zero
5x^2  x  22 = 0
(5x11)(x+2) = 0
two vertical asymptotes:
x = 11/5 and x = 2