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March 29, 2017

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The system shown in the figure below consists of a m1 = 5.52-kg block resting on a frictionless horizontal ledge. This block is attached to a string that passes over a pulley, and the other end of the string is attached to a hanging m2 = 2.76-kg block.The pulley is a uniform disk of radius 7.86 cm and mass 0.592 kg. Calculate the speed of the m2 = 2.76-kg block after it is released from rest and falls a distance of 2.08 m. Calculate the angular speed of the pulley at this instant.

  • physics - ,

    m₁a= T₁
    m₂a= m₂g-T₂

    Iε=M => mR²•a/2R = (T₂-T₁)R,
    T₂-T₁= ma/2,
    a= m₂g/( m₁+m₂+m/2)=...

    a=v²/2s
    v=sqrt(2as)=...
    ω=v/R=...

  • physics - ,

    What is "s"? and what mass is the unlabeled m referring to in the first acceleration equation?

  • physics - ,

    s=2.08 m
    m=0.592 kg
    R=0.0786 m

    a is the acceleration of the system (m1+m2)

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