Posted by **Daniel** on Saturday, March 23, 2013 at 7:29am.

• A car moves 26 km due east then 14 km due north. It then turns along a path running north-west with 15 km, then 17 km due west. If the time for the entire journey is 2 hrs.

• Find;

• (a) the car’s average speed in m/s

• (b) the car’s average velocity in km/h

- University of Ghana -
**black_widow**, Saturday, March 23, 2013 at 9:05am
Average speed = (26+14+15+17)/2 km/h

=36 km/h

=36x1000/(60x60) m/s

=10 m/s

- University of Ghana -
**drwls**, Saturday, March 23, 2013 at 9:23am
(a) For the average speed, divide the total distance travelled, in ANY direction, by 2 hours. That would result in:

(26 + 14 + 15 + 17)/2 = 36 km/h = 36000 m/3600 s = 10.0 m/s

(b) For the average velocity, divide the distance between the starting and finishing points (a vector sum) by 2 hours.

The vector velocity from start to finish is

(26i + 14j -10.607i + 10.607j -17i)/2

= (1.607i -24.607j)/2

(i represents the east direction and j represents the north direction)

= 0.803 i -12.304 j

The magnitude of the average velocity (average speed) is 12.33 km/h, and the direction is slightly north of west.

- University of Nairobi -
**Kim**, Saturday, June 22, 2013 at 4:54am
Simple question

:D

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