Sunday

April 20, 2014

April 20, 2014

Posted by **Dylan** on Saturday, March 23, 2013 at 2:20am.

This is what I did and would like verification of my answer.

2*4.183*-50 = -418.3 kJ

I then subtracted that from my total heat energy:

485.3 - 418.3 = 67 kJ

For latent fusion:

67 = 335*m

m = 0.2 kg of ice

My original mass of water was 2 kg so the composition of the final mixture would be:

0.2 kg of ice

1.8 kg of water

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