Posted by black_widow on Saturday, March 23, 2013 at 12:08am.
why not just use ||, since / is usually used for division?
||(2x-1)(x+3)|-4| < 1
You have four cases to consider:
|(2x-1)(x+3)|-4 positive or negative, and within those,
(2x-1)(x+3) positive or negative
you will quite possibly end up with a solution set comprising 4 intervals
still cant solve it.....
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