Simplify 2/root 3(49)
I solved it as 2 root 3(49) over 49. the system that I entered it in says this is incorrect. Help I need to understand how to do this problem with steps. I am so confused.
Thanks
To simplify the expression 2/√3(49), we need to apply the order of operations (PEMDAS/BODMAS) and simplify it step-by-step.
Step 1: Simplify √3
Since √3 cannot be simplified further (it is the square root of 3), we leave it as √3 in the expression.
Step 2: Multiply 2 and √3
Multiply 2 by √3:
2 * √3 = 2√3
Step 3: Multiply 2√3 by 49
Multiply 2√3 by 49:
2√3 * 49 = 98√3
Therefore, the simplified form of 2/√3(49) is 98√3.
Note: It seems that you made an error when writing the expression as 2√3(49)/49. Make sure to multiply the entire expression by 49, not just the 2√3 part.
To simplify the expression 2/√3 * 49, we can break it down into two steps: simplifying the square root and then multiplying.
Step 1: Simplify the square root
√3 is the square root of 3. To simplify it, we need to find the perfect square that divides 3. Since 3 is a prime number, we cannot simplify it further. Therefore, √3 remains the same.
Step 2: Multiply
Now that we have simplified the square root, we can multiply the remaining numbers. Multiply 2/√3 by 49:
(2/√3) * 49
To multiply fractions, we multiply the numerators (top numbers) together and the denominators (bottom numbers) together:
2 * 49 / √3
2 * 49 = 98, so the expression becomes:
98 / √3
To simplify further, we can rationalize the denominator. This means we need to multiply both the numerator and denominator by the same value to eliminate the square root in the denominator.
To rationalize the denominator, we multiply the expression by the conjugate of the denominator, which is √3. By multiplying the numerator and denominator by √3, we will eliminate the square root in the denominator.
(98 / √3) * (√3 / √3)
Multiplying the numerators and denominators, we get:
98√3 / 3
Therefore, the simplified expression is:
98√3 / 3
I don't know where the 3 comes in
do you mean 2/√(3(49) ) ?
or is it 2/cuberoot(49) ?
"root" is not clear enough, is it squareroot, or ....