Posted by Jill on Friday, March 22, 2013 at 9:26pm.
mols NH4Cl = grams/molar mass = about 0.005 but you need to do that more accurately. Then 0.005/0.115 = about 0.05
........NH4^+ + H2O ==>H3O^+ + NH3
I.......0.05M...........0......0
C........-x.............x......x
E......0.05-x...........x......x
Ka for NH4^+ = (Kw/Kb for NH3) = (x)(x)/(0.05-x). Substitute from above and solve for x = (H3O^+) then convert to pH.
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