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A ship maneuvers to within 2500 m of an island's 1800 m high mountain peak and fires a projectile at an enemy ship 610 m on the other side of the peak, as illustrated in Figure 3-29. If the ship shoots the projectile with an initial velocity of v = 248 m/s at an angle of θ = 74°, how close to the enemy ship does the projectile land?

  • Physics -

    find time in air:

    0=0+248sin74 t-4.9t^2

    now, with that time in air.
    horizontal range=248cos74*t
    figure that out, then since the distance to the ship is 610+2500

    you can figure the distance the projectile is from the ship.

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