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calculus

posted by on .

Find dy/dx.
y^3 = 8x^3 + 4x

  • calculus - ,

    3y^2 dy=24x^2 dx + 4dx

    dy/dx=(8x^2+1)/(y^2) check that

  • calculus - ,

    bob probably meant to type

    dy/dx = (8x^2 + 4/3)/(y^2)

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