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January 30, 2015

January 30, 2015

Posted by **akash** on Friday, March 22, 2013 at 8:31pm.

y^3 = 8x^3 + 4x

- calculus -
**bobpursley**, Friday, March 22, 2013 at 8:43pm3y^2 dy=24x^2 dx + 4dx

dy/dx=(8x^2+1)/(y^2) check that

- calculus -
**Reiny**, Friday, March 22, 2013 at 11:58pmbob probably meant to type

dy/dx = (8x^2 + 4/3)/(y^2)

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