Solve for y: 5x+7y=23
5x+7y=23
7y = 23 - 5x
y = (23 - 5x) / 7
Three times the square of a number minus twice the same number is 8. Find all such numbers.
To solve for y in the equation 5x + 7y = 23, we need to isolate y on one side of the equation. Follow these steps:
Step 1: Start with the equation 5x + 7y = 23.
Step 2: Subtract 5x from both sides of the equation to move the term containing x to the other side. This results in 7y = 23 - 5x.
Step 3: Simplify the right side of the equation. In this case, it becomes 7y = -5x + 23.
Step 4: Divide both sides of the equation by 7 to isolate y. This gives us y = (-5x + 23) / 7.
Therefore, the solution for y is y = (-5x + 23) / 7.