Saturday

December 20, 2014

December 20, 2014

Posted by **zachary** on Friday, March 22, 2013 at 6:24pm.

1.4 = e ^ (0.03k)

Now take the natural logarithm of both sides to solve for ,

ln 1.4 = ln e ^ (0.03k)

ln 1.4 = 0.03k * ln e

Recall that ln e = 1.

ln 1.4 = 0.03 k

Solve for k.

Then try part b.

For # 2,

y = 3 + e ^ (4 - x). Swap x and y and then solve for y.

x = 3 + e ^ (4 - y)

x - 3 = e ^ (4 - y)

Now take the natural logarithm of both sides and solve for y.

- urgent urgent algebra / precalculas -
**Henry**, Saturday, March 23, 2013 at 7:21pme^(0.03k) = 1.4

0.03k*Lne = Ln1.4

0.03k*1 = 0.33647

k = 11.22

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