Posted by John on Friday, March 22, 2013 at 5:17pm.
Your value of a should be -1 , or else your frog would jump up into space.
Assuming he starts at the origin, (I don't have your diagram), the equation would be
height = -(x -4.5)^2 + 3
2nd:
I am going to place the centre of the doorway at (0,0)
so the equation is
y = ax^2 + 16
but (4,0) lies on it
0 = a(16) + 16
a = -1
y = -x^2 + 16 is the equation of the arch.
so when y = 7
7 = -x^2 + 16
x^2 = 9
x = ± 3
the box would be 6 feet wide.
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