Posted by anoynomous on Friday, March 22, 2013 at 2:22pm.
how can we show that there is no constant
in the expansion of [2x – (x^2/4)]^9

mathsbinomial theorem  Reiny, Friday, March 22, 2013 at 2:34pm
general term
= C(9,n) (2x)^(9n) (x^2/4)^n
= C(9,n) 2^(9n) x^(9n) (1/4)^n x^2n)
= C(9,n) (2^(9n)(1/4)^n x^(9+n)
to have a constant, the exponent of x^(9+n) must be zero
so 9+n = 0
n = 9
BUT, n must be a positive integer, so there is no constant term in the expansion.
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