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October 25, 2014

October 25, 2014

Posted by **pam** on Friday, March 22, 2013 at 2:08pm.

- huh ??? -
**Damon**, Friday, March 22, 2013 at 2:14pmI think the area of the sides (without top and bottom) is

A = 2 pi r h

(not h^2)

A = 2 (3.14) (1.3)(6.2) = 50.6 in^2

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