Physics
posted by Renay on .
A ball is projected upward at time t= 0.0s, from a point on the roof 10m above the ground. The ball rises, then falls until it strikes the ground. The initial velocity of the ball is 58.5 m/s. At time t=5.97s, what is the approximate velocity of the ball? Neglect air resistance.

Solve this equation using t = 5.97:
V = Vo  g t = 58.5  9.8 t
That will be zero, indicating that the ball is at its highest elevation. 
Why'd you use 9.8?

Because the acceleration of gravity (g) is 9.8 m/s^2.

Oh, okay, thanks.

jip;

ayyy lmao