Posted by **Renay** on Friday, March 22, 2013 at 12:58pm.

A ball is projected upward at time t= 0.0s, from a point on the roof 10m above the ground. The ball rises, then falls until it strikes the ground. The initial velocity of the ball is 58.5 m/s. At time t=5.97s, what is the approximate velocity of the ball? Neglect air resistance.

- Physics -
**drwls**, Friday, March 22, 2013 at 1:02pm
Solve this equation using t = 5.97:

V = Vo - g t = 58.5 - 9.8 t

That will be zero, indicating that the ball is at its highest elevation.

- Physics -
**Renay**, Friday, March 22, 2013 at 1:07pm
Why'd you use 9.8?

- Physics -
**drwls**, Friday, March 22, 2013 at 1:08pm
Because the acceleration of gravity (g) is 9.8 m/s^2.

- Physics -
**Renay**, Friday, March 22, 2013 at 1:09pm
Oh, okay, thanks.

- Physics -
**l;lpkj**, Monday, November 9, 2015 at 12:58pm
jip-;

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