posted by Renay on .
A ball is projected upward at time t= 0.0s, from a point on the roof 10m above the ground. The ball rises, then falls until it strikes the ground. The initial velocity of the ball is 58.5 m/s. At time t=5.97s, what is the approximate velocity of the ball? Neglect air resistance.
Solve this equation using t = 5.97:
V = Vo - g t = 58.5 - 9.8 t
That will be zero, indicating that the ball is at its highest elevation.
Why'd you use 9.8?
Because the acceleration of gravity (g) is 9.8 m/s^2.
Oh, okay, thanks.