What is the value of e^i(pi)?
where i^2 =-1 ,e =exponential
ahhhh!
http://www.mathscareers.org.uk/viewItem.cfm?cit_id=382931
http://en.wikipedia.org/wiki/Euler's_identity
To find the value of e^i(pi), we can make use of Euler's formula. Euler's formula states that:
e^(ix) = cos(x) + i*sin(x)
In this case, x = pi. So, let's substitute x = pi into Euler's formula:
e^(i*pi) = cos(pi) + i*sin(pi)
Now, we know that cos(pi) = -1 and sin(pi) = 0. So, we can substitute these values:
e^(i*pi) = -1 + i*0
Since anything multiplied by 0 is equal to 0, we have:
e^(i*pi) = -1
Therefore, the value of e^(i*pi) is -1.