Posted by Jordan on Friday, March 22, 2013 at 8:31am.
Assuming the teeth are equally spaced, the circumference of the front sprocket is twice that of the real sprocket, or
for each turn of the front we have two turns of the rear
Then at 50 rpm, the rear will will turn 100 rpm
circumf of rear wheel = 27π inches
distance covered in 1 minute (from rpm=rotations per minute)
27π(100) inches
or 2700π inches per minute
= 706.858.. ft/min
= appr 8.03 mph
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