math
posted by pam on .
a launched rocket has an altitude, in meters, given by the polynimial h+vt4.9t^2 where h is the height, in meters, from which the launch occurs, at velocity v in meters per second, and t is the number of seconds for which the rocket is airborne. If a rocket is launched from the top of a tower 100 meters high with an initial upwrd speed of 20 meters per second. What will the height be after 4 seconds?

h = vt  4.9t^2
from the given ....
h = 20t  4.9t^2 + 100 , where h is the height above ground
so after 4 seconds
h = 20(4)  4.9(16) + 100
= 41.6 m above the ground