a launched rocket has an altitude, in meters, given by the polynimial h+vt-4.9t^2 where h is the height, in meters, from which the launch occurs, at velocity v in meters per second, and t is the number of seconds for which the rocket is airborne. If a rocket is launched from the top of a tower 100 meters high with an initial upwrd speed of 20 meters per second. What will the height be after 4 seconds?

h = vt - 4.9t^2

from the given ....

h = 20t - 4.9t^2 + 100 , where h is the height above ground

so after 4 seconds
h = 20(4) - 4.9(16) + 100
= 41.6 m above the ground

A square garden has a side length of 5.8 meters what is the perimeter of the garden ? what is the area pf thd garden?

To find the height of the rocket after 4 seconds, we need to substitute the values into the equation h + vt - 4.9t^2 and solve for h.

Given:
Initial height (h) = 100 meters
Velocity (v) = 20 meters/sec
Time (t) = 4 seconds

Substituting the values into the equation:
h + vt - 4.9t^2 = 100 + 20(4) - 4.9(4)^2

Simplifying the equation step by step:
h + vt - 4.9t^2 = 100 + 80 - 4.9(16)
h + vt - 4.9t^2 = 100 + 80 - 78.4
h + vt - 4.9t^2 = 101.6

Therefore, the height of the rocket after 4 seconds is 101.6 meters.