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a launched rocket has an altitude, in meters, given by the polynimial h+vt-4.9t^2 where h is the height, in meters, from which the launch occurs, at velocity v in meters per second, and t is the number of seconds for which the rocket is airborne. If a rocket is launched from the top of a tower 100 meters high with an initial upwrd speed of 20 meters per second. What will the height be after 4 seconds?

  • math - ,

    h = vt - 4.9t^2
    from the given ....

    h = 20t - 4.9t^2 + 100 , where h is the height above ground

    so after 4 seconds
    h = 20(4) - 4.9(16) + 100
    = 41.6 m above the ground

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