Posted by **Kris** on Thursday, March 21, 2013 at 9:22am.

Hello,

This is the last of questions I have for my practice assignment. Again I will put what I got. Thanks for your help.

1.) Solve the system using substitution. Write answer as an ordered pair.

4x+2y=8

-5x-2=y

A.) First equation (-2,8)

B.) Second equation (-2,8)

I put A

2.) Solve the system using elimination. If the system is linearly dependent, state the general solution in terms of a parameter.

4x-2y+2z=2

-x+y-3z=-4

4x-3y+7z=9

A.) (-1,-7,0)

B.) (3,3,2)

C.) (2z-3, 5z-7, z)

D.) no solution, inconsistent

I got D.

3. Solve using the method of your choice.

y-2^x^2+2x=0

y=4^x+8

A) (4,2^24)

B) (-4, 2^8)

C) (4, 2^24) (-4, 2^8)

D) (4, 2^24) (-4, -2^8)

I got B

- Algebra Multiple Choice -
**Knights**, Thursday, March 21, 2013 at 9:34am
1. From substitution we get 4-2x= -5x-2

So, 3x = -6, x=-2, so y = 8: (-2,8)

2. Should be D

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