Posted by Sandile on Thursday, March 21, 2013 at 3:07am.
maximum height reached by the sand bag is..change in y=(vf+vi/2).change in time..solution=(0+5/2)3=(2.5)(3)=7.5+60=67.5m
d).magnitude and direction of the sandbag's velocity..solution=vf=vi+a(change time)=0=5+(9.8)(3)=34.4 m/seconds
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