Posted by **Sandile** on Thursday, March 21, 2013 at 3:07am.

A hot air balloon is rising upwards at a constant velocity of 5 m/s . When the balloon is 60 m above the ground , a sand bag is released from it and allowed to free fall . Ignore the effect of air resistance and assume that the balloon continues to move with the same constant velocity.

(a) Describe the motion of the sand bag when it was dropped to free fall.

(b)Where is the sand bag after 3 seconds?

(c)What is the maximum height reached by the sand bag .

(d)What is the magnitude and direction of the sandbag's velocity at the specific moment when it was released?

(e)How far apart will be the sandbag and the balloon be after 3 seconds?

(f)How long will it take the sandbag to reach the ground after it has been released?

- physical science -
**Jossie**, Thursday, March 21, 2013 at 5:07am
maximum height reached by the sand bag is..change in y=(vf+vi/2).change in time..solution=(0+5/2)3=(2.5)(3)=7.5+60=67.5m

- physical science -
**Jossie**, Thursday, March 21, 2013 at 5:12am
d).magnitude and direction of the sandbag's velocity..solution=vf=vi+a(change time)=0=5+(9.8)(3)=34.4 m/seconds

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