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posted by Jen on Thursday, March 21, 2013 at 3:04am.
What is the solubility of AgCrO4 (Ksp= 9.0 x 10^-12) in distilled water?
Ag2CrO4 ==> 2Ag^+ + CrO4^2- ...x........2x.......x Ksp = (Ag^+)^2(CrO4^2-) Substitute and solve for x = (CrO4^2-) = (Ag2CrO4)
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