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April 24, 2014

April 24, 2014

Posted by **Jacob** on Thursday, March 21, 2013 at 1:33am.

- Applied Calculus -
**Jacob**, Thursday, March 21, 2013 at 1:40amI know how to solve it to get .21, but I need to write it using positive exponents only. I know this isn't technically Calculus, but it is what we are reviewing currently. I am a bit rusty with this one, can't quite remember how to do it. I am trying some different things, but would greatly appreciate an explanation. Thank you!

- Applied Calculus -
**Steve**, Thursday, March 21, 2013 at 4:36amsince 4=2^2,

4^(-3/2) = (2^2)^(-3/2) = 2^-3

2^(3/4) * 2^-3 = 2^(3/4-3) = 2^(-9/4)

= 1/(4*2^(1/4)) = 0.21

Or, if you want positive exponents from the get-go,

4^(-3/2) = 1/4^(3/2)

2^(3/4) / 4^(3/2)

= 2^(3/4) / 2^3

= 1 / 2^(9/4)

= 0.21

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