Physics
posted by Troy on .
If a vehicle starts at 31 km/h and only travels 4.7m in 1.1 seconds due to deceleration, how fast is it going after 1.1 seconds?

change in y=vi change in time+1/2a change in time squared..4.7=31(1.1)+1/2(9.8)(1.1)^2=31.1/4.7=7.26 k.h