a piece of rope 3m 66 m long was cut into 2 pieces. the longer piece was twice as long as the shorter piece. What was the length of the longer piece?

If 3m 66m mean 3 m 66 cm then:

3 m 66 cm = 3.66 m

L = Longer piece

S = Shorter piece

L = 2 S

L + S = 3.66 m

2 S + S = 3.66 m

3 S = 3.66 m Divide both sides by 3

S = 3.66 m / 3

S = 1.22 m = 1 m 22 cm

L = 2 S = 2 * 1.22 m = 2.44 m = 2 m 44 cm

How do we solve this problem a rope 3m 66cm was cut into 2pieces.The linger piece was twice as long as the shorter piece.What was the length of the longer piece?

To solve this problem, let's assign variables to represent the lengths of the two pieces of rope.

Let's say the length of the shorter piece is 'x' meters. Since the longer piece is twice as long as the shorter piece, we can represent the length of the longer piece as '2x' meters.

The total length of the two pieces is given as 3.66 meters. So, we can set up an equation:

x + 2x = 3.66

Combining like terms:

3x = 3.66

To solve for 'x', we can divide both sides of the equation by 3:

x = 3.66 / 3

Simplifying the right side:

x ≈ 1.22

So, the length of the shorter piece is approximately 1.22 meters.

To find the length of the longer piece, we can substitute this value back into our equation:

2x = 2 * 1.22

Multiplying:

2x ≈ 2.44

So, the length of the longer piece is approximately 2.44 meters.