Homework Help: Chemistry

Posted by Robert on Wednesday, March 20, 2013 at 10:43pm.

How many milliliters of 6.50 M HCl(aq) are required to react with 5.95 g of an ore containing 35.0% Zn(s) by mass?

Chemistry - DrBob222, Wednesday, March 20, 2013 at 11:18pm
Zn + 2HCl ==> Zn^2+ ....
g Zn = 5.95*0.35 = ?
mols Zn = ?g Zn/atomic mass Zn

Convert mols Zn to mols HCl using the coefficients.
M HCl = mols HCl/L HCl. You know M and mols, solve for L and convert to mL.

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