Posted by Adam on Wednesday, March 20, 2013 at 10:22pm.
let x = log (base3) 5
then 3^x = 5 , clearly x > 1 ,
because 3^1 = 3 and 3^2 = 25 ,so x must be between 1 and 2
let y = log(base5)^3
then 5^y = 3 , clearly y < 1,
because 5^0 = 1 and 5^1 = 5
so y has to be between 0 and 1
so x ≠ y
and the two log expressions cannot be equal
fantastic, makes so much sense now, thx
and btw 3^2 = 25 is typo
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