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December 18, 2014

December 18, 2014

Posted by **Anonymous** on Wednesday, March 20, 2013 at 9:05pm.

- algebra 1 -
**Reiny**, Wednesday, March 20, 2013 at 10:30pmThe way you typed it, there is no need to use elimination

from 52a+5 = 10

52a = 5

a = 5/52

sub into 3a + b = 10

3(5/52) + b = 10

times 52

15 + 52b = 520

52b = 505

b = 505/52

Whatever would make me think that you have a typo

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