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Calculus

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Find the absolute maximum value and the absolute minimum value,
f(x)= (x +1 )/ (x-1) on [2, 4]

  • Calculus -

    f'(x) = (x-1 - (x+1) )/(x-1)^2 = -2/(x-1)^2
    = 0 for a max/min

    no solution
    so look at the endpoints:
    f(2) = 3/1 = 3
    f(4) = 5/3

    the min is 5/3, the max is 3

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