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March 1, 2015

March 1, 2015

Posted by **Cam** on Wednesday, March 20, 2013 at 8:56pm.

f(x)= (x +1 )/ (x-1) on [2, 4]

- Calculus -
**Reiny**, Wednesday, March 20, 2013 at 10:20pmf'(x) = (x-1 - (x+1) )/(x-1)^2 = -2/(x-1)^2

= 0 for a max/min

no solution

so look at the endpoints:

f(2) = 3/1 = 3

f(4) = 5/3

the min is 5/3, the max is 3

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