posted by Stephen on .
Given Zn(NO3)2 + (NH4)2S = ZnS + 2NH4NO3 (molar mass of Zn(NO3)2 189 g, molar mass of (NH4)2S 68 g), what is the molarity of a 250 ml solution if you have 123 g of zinc nitrate?
Moles zinc nitrate = grams zinc nitrate/molar mass.
M = moles/L.
I don't know what the equation has to do with the post. Please let me know if I have interpreted the problem incorrectly.