Posted by Manboob on .
A 1.00 kg pendulum bob is released from a height of 0.200 m. Its speed at the bottom of its swing is 1.95 m/s on the first pass. How much energy is lost due to friction during one complete swing of the pendulum?
I get Ep=mgh 0.2*9.8*1 =1.96
then i get Ek=1/2mv^2 1/2*1*1.95^2 = 1.90125
then i minus these 2 but get the wrong answer what are the correct steps?