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Tangent Lines (2)-Calculus

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find an equation of the line tangent to y= sqrt(25-x^2) at the point (3,4)

i got y= x/8 + 29/8

this is wrong. but im not sure why. can you explain thank you

  • Tangent Lines (2)-Calculus - ,

    y=√(25-x^2)
    y' = -x/√(25-x^2)
    y'(3) = -3/4

    so, now you have a point and a slope. The line is thus

    y-4 = -3/4 (x-3)

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