Friday

August 1, 2014

August 1, 2014

Posted by **Greg** on Wednesday, March 20, 2013 at 12:34am.

write the equation of this line

i get y= 3x-1 yet it's wrong. please explain thank you

- Tangent Lines-Calculus -
**Steve**, Wednesday, March 20, 2013 at 11:12amy=(x^2+3) / (x+3)

^{½}

y(1) = 4/2 = 2

y' = 3(x^2+4x-1) / 2(x+3)^{3/2}

y'(1) = 3(4)/2*8 = 3/4

so, now you have a point (1,2) and a slope (3/4)

y-2 = 3/4 (x-1)

**Related Questions**

calculus - Consider the curve defined by 2y^3+6X^2(y)- 12x^2 +6y=1 . a. Show ...

Calculus - Consider line segments which are tangent to a point on the right ...

calculus - Consider line segments which are tangent to a point on the right half...

Calculus - If F(x)=x^3−7x+5, use the limit definition of the derivative to...

Calculus - Please help this is due tomorrow and I dont know how to Ive missed a ...

Help Calc.! - original curve: 2y^3+6(x^2)y-12x^2+6y=1 dy/dx=(4x-2xy)/(x^2+y^2+1...

please help; calc - original curve: 2y^3+6(x^2)y-12x^2+6y=1 dy/dx=(4x-2xy)/(x^2+...

calculus - Write the equation of the tangent line to the curve at the indicated ...

Calculus - the slope of the tangent line to the curve y=(3/x) at the point (6,0....

Calculus 251 - The slope of the tangent line to the curve y= 3x^3 at the point...