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February 1, 2015

February 1, 2015

Posted by **Greg** on Wednesday, March 20, 2013 at 12:34am.

write the equation of this line

i get y= 3x-1 yet it's wrong. please explain thank you

- Tangent Lines-Calculus -
**Steve**, Wednesday, March 20, 2013 at 11:12amy=(x^2+3) / (x+3)

^{½}

y(1) = 4/2 = 2

y' = 3(x^2+4x-1) / 2(x+3)^{3/2}

y'(1) = 3(4)/2*8 = 3/4

so, now you have a point (1,2) and a slope (3/4)

y-2 = 3/4 (x-1)

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