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March 2, 2015

March 2, 2015

Posted by **zachary** on Tuesday, March 19, 2013 at 11:44pm.

f(X) = 1/X-5,g(x)-6/x

question 2

find inverse, domain range and asymatotes of each function

f(x)=3+e^4-x

can some one help me please been stuck on these for 2 days need help solving thank you

- urgent urgent algebra -
**Steve**, Wednesday, March 20, 2013 at 11:27amassuming a typo, I see

f(x) = 1/(x-5)

g(x) = 6/x

so, f◦g = f(g) = 1/(g-5)

= 1/((6/x)-5)

= 1/((6-5x)/x)

= x/(6-5x)

check for some value, say, x=2:

g(2) = 3

f(3) = -1/2

(f◦g)(2)=2/(6-5*2) = 2/-4 = -1/2

y=3+e^(4-x)

y-3 = e^(4-x)

ln(y-3) = 4-x

x = 4 - ln(y-3)

so, f^-1(x) = 4 - ln(x-3)

domain of f is all reals

range is y>3

asymptote is y=3

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