Posted by **Robert** on Tuesday, March 19, 2013 at 9:49pm.

59.0 mL of a 1.80 M solution is diluted to a total volume of 268 mL. A 134-mL portion of that solution is diluted by adding 171 mL of water. What is the final concentration? Assume the volumes are additive.

- Chemistry -
**Devron**, Tuesday, March 19, 2013 at 10:00pm
1.80*(59/268)=concentration

concentration*(134/171)= concentration 2

- Chemistry -
**DrBob222**, Tuesday, March 19, 2013 at 11:10pm
almost

1.80M x (59.0 mL/268 mL) = about 0.4 but that is not exact.

Then 0.4 x [134 mL/(134 mL + 171 mL)]

- Chemistry -
**Devron**, Tuesday, March 19, 2013 at 11:14pm
Read it halfway; I thought it was going to say making a solution to 171mL using 134mL of the previous. Dr. Bob222 is correct.

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