Chemistry
posted by Robert .
59.0 mL of a 1.80 M solution is diluted to a total volume of 268 mL. A 134mL portion of that solution is diluted by adding 171 mL of water. What is the final concentration? Assume the volumes are additive.

1.80*(59/268)=concentration
concentration*(134/171)= concentration 2 
almost
1.80M x (59.0 mL/268 mL) = about 0.4 but that is not exact.
Then 0.4 x [134 mL/(134 mL + 171 mL)] 
Read it halfway; I thought it was going to say making a solution to 171mL using 134mL of the previous. Dr. Bob222 is correct.