Consider a 14.3 g sample of steam initially at 100*C. How many kilojoules equal the amount of energy emitted by this sample as it condenses, cools to it's freezing point, and subsequently freezes to form ice at 0*C

To calculate the amount of energy emitted by the sample as it undergoes condensation, cooling, and freezing, we need to consider the specific heat capacity and heat of fusion of water.

1. First, let's calculate the energy released during the condensation process. The specific heat capacity of steam is 2.03 J/g°C. We know that the sample of steam initially at 100°C will condense to form water at 100°C.

The formula to calculate the energy emitted (Q) during the condensation process is:
Q = mass × specific heat capacity × temperature change

The mass is given as 14.3 g, the specific heat capacity is 2.03 J/g°C, and the temperature change is (100 - 100)°C = 0°C.

Therefore, the energy emitted during condensation is:
Q = 14.3 g × 2.03 J/g°C × 0°C = 0 J

As there is no change in temperature during condensation, there is no energy emitted during this process.

2. Next, let's calculate the energy released during the cooling process. The specific heat capacity of water is 4.18 J/g°C. We need to cool the water from 100°C to its freezing point of 0°C.

Using the same formula as before, the energy emitted during cooling is:
Q = mass × specific heat capacity × temperature change

The mass is still 14.3 g, the specific heat capacity is 4.18 J/g°C, and the temperature change is (100 - 0)°C = 100°C.

Therefore, the energy emitted during cooling is:
Q = 14.3 g × 4.18 J/g°C × 100°C = 5957.14 J or 5.96 kJ

3. Finally, let's calculate the energy released during the freezing process. The heat of fusion of water is 334 J/g. We need to freeze the water at 0°C.

The formula to calculate the energy emitted during freezing is:
Q = mass × heat of fusion

Again, the mass is 14.3 g, and the heat of fusion is 334 J/g.

Therefore, the energy emitted during freezing is:
Q = 14.3 g × 334 J/g = 4776.2 J or 4.78 kJ

To get the total amount of energy emitted during the entire process, we sum up the results:
Total energy emitted = energy emitted during cooling + energy emitted during freezing
Total energy emitted = 5.96 kJ + 4.78 kJ = 10.74 kJ

Therefore, the amount of energy emitted by the sample as it condenses, cools, and freezes is approximately 10.74 kilojoules.