Thursday

July 24, 2014

July 24, 2014

Posted by **Anonymous** on Tuesday, March 19, 2013 at 6:09pm.

A. Find the percentage of adult green sea urchins with weighs between 50g and 60g

My answer/work: normalcdf (50, 60, 52, 17.2) = .225, 23%

B. Obtain the percentage of adult green sea urchins with weights above 40g

My answer/work: normalcdf (40, e99, 52, 17.2) = .757, 76%

C. Determine and interpret the 90% percentile for the weights

My answer/work: invnorm: .9, 0,1) =1.28

z-52 + (1.28)*(17.2)

z= 74.04%

I'm a little unsure if I got C correct. As for the rest I'm wondering if I did them correctly. If not, could someone lean me to the right direction? Thank you :)

- Statistics -
**PsyDAG**, Wednesday, March 20, 2013 at 1:30pmA. Z = (score-mean)/SD

Z = (50-52)/17.2 = -2/17.2 = -.12

Z = (60-52)/17.2 = 8/17.2 = .47

Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability related to the Z scores.

.0478 +.1808 = .2286 = 23%

B. Similar process.

C. Correct

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