Posted by **Amanda** on Tuesday, March 19, 2013 at 5:49pm.

f(x)=2ln(x^2+3)-x Domain [-3,5]

how do i find the absolute maximum value of this?

- Calc -
**MathMate**, Tuesday, March 19, 2013 at 7:47pm
To find the absolute maximum of a function within a finite domain, you can do:

find f'(x) and equate to zero to find the relative maxima and minima.

In this case, f'(x)=0 at x=1 and x=3.

By checking with f"(x) or otherwise, you will find that x=1 is a minimum, and x=3 is a maximum.

Evaluate f(3)=2ln(12)-3 = 1.97 approx.

Now evaluate function f(x) at limits of domain, namely f(-3)=2ln(12)+3=7.97 approx., and f(5)=2ln(28)-5=1.66 appro.

Thus the absolute maximum is at x=-3.

## Answer this Question

## Related Questions

- Calc - f(x)=2ln(x^2+3)-x Domain [-3,5] how do i find the absolute maximum value ...
- Calc - f(x)=2ln(x^2+3)-x Domain [-3,5] how do i find the absolute maximum value ...
- Calc - Let f be the function given by f(x)=2ln(x^2+3)-x with domain -3 is less ...
- Calculus (pleas help!!!) - Find the absolute maximum and absolute minimum ...
- Calculus (pleas help!!!) - Find the absolute maximum and absolute minimum values...
- Differential Equations (Another) Cont. - For the following initial value problem...
- Calculus - Find the absolute extrema of the function. (Round your answer to ...
- Calculus - Find the absolute extrema of the function. (Round your answer to ...
- math/calculus - f(x)= the absolute value of x^2-6x-7 a) Find a piecewise defined...
- calc - Let f(x)=x^3-3x^2 find the absolute maximum value of f(x) on the interval...