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April 18, 2014

April 18, 2014

Posted by **Hasane** on Tuesday, March 19, 2013 at 4:29pm.

3/(log_2 (a)) - 2/(log_4 (a)) = 1/(log_(1/2)(a))

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**Steve**, Tuesday, March 19, 2013 at 4:54pm3/(log_2 (a)) - 2/(log_4 (a)) = 1/(log_(1/2)(a))

since 4 = 2^2, log_4(a) = 1/2 log_2(a)

since 1/2 = 2^-1, log_(1/2)(a) = -log_2(a)

so, if we let x = log_2(a), we have

3/x - 2/(x/2) = 1/(-x)

3/x - 4/x = -1/x

(4-3)/x = -1/x

1/x = -1/x

???

Is there a typo somewhere ?

- math -
**Hasane**, Tuesday, March 19, 2013 at 4:59pmi.imgur[dot]com/hE0sWBt[dot]gif

- math -
**Hasane**, Tuesday, March 19, 2013 at 5:00pmMake sure its just like that, it has to be solvable o.o

- math -
**Hasane**, Tuesday, March 19, 2013 at 5:01pmer "prove-able"

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