Posted by Hasane on Tuesday, March 19, 2013 at 4:29pm.
Prove:
3/(log_2 (a))  2/(log_4 (a)) = 1/(log_(1/2)(a))

math  Steve, Tuesday, March 19, 2013 at 4:54pm
3/(log_2 (a))  2/(log_4 (a)) = 1/(log_(1/2)(a))
since 4 = 2^2, log_4(a) = 1/2 log_2(a)
since 1/2 = 2^1, log_(1/2)(a) = log_2(a)
so, if we let x = log_2(a), we have
3/x  2/(x/2) = 1/(x)
3/x  4/x = 1/x
(43)/x = 1/x
1/x = 1/x
???
Is there a typo somewhere ?

math  Hasane, Tuesday, March 19, 2013 at 4:59pm
i.imgur[dot]com/hE0sWBt[dot]gif

math  Hasane, Tuesday, March 19, 2013 at 5:00pm
Make sure its just like that, it has to be solvable o.o

math  Hasane, Tuesday, March 19, 2013 at 5:01pm
er "proveable"
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