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March 26, 2017

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If a snowball melts so that its surface area decreases at a rate of 4 cm2/min, find the rate at which the diameter decreases when the diameter is 12 cm.

  • Calculus - ,

    a = 4 pi r^2 = pi d^2
    da/dt = 2 pi d dd/dt
    Now just solve
    -4 = 2 pi (12) dd/dt

  • Calculus - ,

    -1/12pi

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