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posted by Cassie on Tuesday, March 19, 2013 at 1:38pm.

What is the domain of the function y=3 sq root 6x+42 ? x ¡Ý 0 x ¡Ü 7 x ¡Ý ¨C6 x ¡Ý ¨C7 I think it is D...?

we need 6x+42 >= 0 for √ to be defined. So, x >= -7

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