Posted by **Peltier** on Tuesday, March 19, 2013 at 10:24am.

A box in a college bookstore contains books, and each book in the box is a history book, an English book or a science book. If one-third of these books are history books and one-sixth are English books, what fraction of the books are science books?

A. 1/3

B. 1/2

C. 2/3

D. 3/4

****please explain this problem to me because I'm sure to have similar ones like this on my real exam.

Thank you in advance

- Arithmetic -
**stranger**, Tuesday, March 19, 2013 at 10:46am
B-1/2

Let no. of books be x

No. of history books equal x into 1/3 I.e.x/3

No. Of English books equal x into 1/3 I.e. x/6

Rest books = no. Of science books

=total books -(history books+English books)

=×-(×/3 +×/6)

=x-(3x/6)

=x-x/2

=x/2 books are of science of total books I.e. x

No of science book is 1/2 of total books

- Arithmetic -
**Peltier**, Tuesday, March 19, 2013 at 10:49am
Thank You

- Arithmetic -
**Kiran**, Monday, October 14, 2013 at 8:36pm
As per the probability rule

Total of all probability is 1

So,

P(History)+P( English)+P( Science) = 1

1/3 + 1/6 + P( Science) = 1

P( Science) = 1- (1/3 + 1/6) = 1 - 1/2

P( Science) = 1/2

- Arithmetic -
**ReneSardinaJr**, Friday, January 8, 2016 at 12:34am
1/3+1/6+ science = Find the LCM (lowest common Multiple).

the LCM for 1/3 is 2.

the LCM for 1/6 is 1.

Multiply both numerator and denominator, which gives you

2/6 + 1/6 = science

then add the 2 and 1

copy the 6 at the bottom which result 3/6 then simplify to lowest form which 1/2.

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