a plane is flying horizontally at an altitude of 420m. A bomb was released, how far horizontally point bomb hit the ground?

The bomb lands right under the plane.

To find the horizontal distance traveled by the bomb before hitting the ground, we need to consider the acceleration due to gravity and the initial velocity of the bomb.

Assuming no air resistance, the bomb will experience a constant downward acceleration of 9.8 m/s² due to gravity.

First, we need to find the time it takes for the bomb to hit the ground. We can do this using the formula for downward motion under constant acceleration:

h = 1/2gt²

Where:
h = 420 m (altitude)
g ≈ 9.8 m/s² (acceleration due to gravity)
t = ?

Rearranging the formula to solve for time (t):

2h = gt²

t² = (2h) / g

t = √((2h) / g)

Substituting the given values:

t = √((2 * 420) / 9.8)
t ≈ 9.12 seconds (rounded to two decimal places)

Now, we can find the horizontal distance traveled by the bomb using the equation:

d = v * t

Where:
d = ?
v = initial horizontal velocity of the bomb (which we assume to be constant)
t = 9.12 seconds

Since the plane is flying horizontally, the bomb will inherit the same horizontal velocity as the plane. Therefore, the horizontal distance traveled by the bomb will depend on the horizontal velocity of the plane.

Without the value of the plane's velocity, we cannot determine the exact distance the bomb traveled horizontally. The question does not provide enough information to calculate it.