3 real numbers that form a geometric progression have sum equal to 175 and product equal to 17576. What is the sum of the largest and smallest numbers?
f the series is a, ar, ar^2
The sum of largest and smallest numbers is a+ar^2
we have, a+ar^2 = 175 - ar and a*ar*ar^2 = 17576
ar = \sqrt[3]{17576}
ar = 26
Therefore, a+ar^2 = 175 - 26 = 149