1) A racing car has a mass of 1525 kg. What is its kinetic energy if it has a speed of 35 m/s?

* 2-3 Conservation of Momentum

2) A 3.0 kg ball is moving at 3 m/s and strikes a 1.5 kg ball moving at -2 m/s. After the collision, the 1.5 kg ball moves to the right at 2 m/s. What is the final velocity at 3.0 kg ball?
FORMULA(2)>> m1vi+m2vi= m1vf+m2vf

3) A 85 kg running back is moving at +12 m/s and strikes a 125 kg linebacker moving at -8.0 m/s. What is the final velocity if they stick together?
FORMULA(3)>> m1vi+m2vi= (m1+m2)vf

>>PLEASE HELP ME!!!!!

1. KE=1/2 mass*velocity^2

2, 3: what is your question? you are given the data, and the formula.

Sure! I'd be happy to help you with these questions step-by-step.

1) To find the kinetic energy of the racing car, we can use the formula:
Kinetic Energy = 1/2 * mass * velocity^2

Given:
Mass of the racing car (m) = 1525 kg
Speed of the racing car (v) = 35 m/s

Substituting these values into the formula:
Kinetic Energy = 1/2 * 1525 kg * (35 m/s)^2

Solving this equation:
Kinetic Energy = 1/2 * 1525 kg * 1225 m^2/s^2
Kinetic Energy = 935937.5 Joules

Therefore, the kinetic energy of the racing car is 935937.5 Joules.

2) In this scenario, we have a collision between two balls. We can use the conservation of momentum principle to solve for the final velocity of the 3.0 kg ball.

The formula for conservation of momentum is:
m1 * v1i + m2 * v2i = m1 * v1f + m2 * v2f

Given:
Mass of the 3.0 kg ball (m1) = 3.0 kg
Initial velocity of the 3.0 kg ball (v1i) = 3 m/s
Mass of the 1.5 kg ball (m2) = 1.5 kg
Initial velocity of the 1.5 kg ball (v2i) = -2 m/s
Final velocity of the 1.5 kg ball (v2f) = 2 m/s

Substituting these values into the formula:
(3.0 kg * 3 m/s) + (1.5 kg * -2 m/s) = (3.0 kg * v1f) + (1.5 kg * 2 m/s)

Solving this equation:
9 kg·m/s + (-3 kg·m/s) = 3.0 kg * v1f + 3 kg·m/s
6 kg·m/s = 3.0 kg * v1f + 3 kg·m/s
6 kg·m/s - 3 kg·m/s = 3.0 kg * v1f
3 kg·m/s = 3.0 kg * v1f
v1f = 1 m/s

Therefore, the final velocity of the 3.0 kg ball is 1 m/s.

3) Similar to the previous question, we can use the conservation of momentum principle to solve for the final velocity when the running back collides with the linebacker.

The formula for conservation of momentum is:
m1 * v1i + m2 * v2i = (m1 + m2) * vf

Given:
Mass of the running back (m1) = 85 kg
Initial velocity of the running back (v1i) = 12 m/s
Mass of the linebacker (m2) = 125 kg
Initial velocity of the linebacker (v2i) = -8.0 m/s

Substituting these values into the formula:
(85 kg * 12 m/s) + (125 kg * -8.0 m/s) = (85 kg + 125 kg) * vf

Solving this equation:
1020 kg·m/s + (-1000 kg·m/s) = 210 kg * vf
20 kg·m/s = 210 kg * vf
vf = (20 kg·m/s) / (210 kg)
vf = 0.0952 m/s (approximately)

Therefore, the final velocity, when the running back and the linebacker stick together, is approximately 0.0952 m/s.

1) To calculate the kinetic energy of the racing car, you can use the formula:

Kinetic Energy = 0.5 * mass * velocity^2

So, in this case, the mass of the car is given as 1525 kg and the speed is 35 m/s. Substituting these values into the formula, we have:

Kinetic Energy = 0.5 * 1525 kg * (35 m/s)^2

To solve this, you need to square the value of the speed (35 m/s), then multiply it by the mass (1525 kg), and finally multiply that result by 0.5.

2) For the collision between a 3.0 kg ball and a 1.5 kg ball, you can use the law of conservation of momentum. The formula to calculate the final velocity after the collision is:

m1 * v1i + m2 * v2i = m1 * v1f + m2 * v2f

In this case, the values given are:
m1 = 3.0 kg (mass of the first ball)
v1i = 3 m/s (initial velocity of the first ball)
m2 = 1.5 kg (mass of the second ball)
v2i = -2 m/s (initial velocity of the second ball)
v2f = 2 m/s (final velocity of the second ball)

Substituting these values into the formula, we have:

3.0 kg * 3 m/s + 1.5 kg * (-2 m/s) = 3.0 kg * v1f + 1.5 kg * 2 m/s

Now, you can solve this equation to find the final velocity of the ball with mass 3.0 kg (v1f).

3) In this scenario, a running back with a mass of 85 kg is moving at a velocity of 12 m/s and strikes a linebacker with a mass of 125 kg, moving at a velocity of -8 m/s. As they stick together, the final velocity of the combined system can be calculated using the law of conservation of momentum, which is similar to the formula used in problem 2.

m1 * v1i + m2 * v2i = (m1 + m2) * vf

Substituting the given values:
m1 = 85 kg (mass of the running back)
v1i = 12 m/s (initial velocity of the running back)
m2 = 125 kg (mass of the linebacker)
v2i = -8 m/s (initial velocity of the linebacker)

Now, you can solve the equation to find the final velocity of the combined system (vf).