Sunday

December 21, 2014

December 21, 2014

Posted by **Christina** on Monday, March 18, 2013 at 3:27pm.

- stats. -
**MathGuru**, Monday, March 18, 2013 at 6:02pmUse this z-score formula for this problem:

z = (x - mean)/(sd/√n)

x = 1.25, 1.50

mean = 1.35

sd = 0.25

n = 40

Calculate two z-scores, then use a z-table to determine probability between the two scores.

I hope this will help get you started.

- stats. -
**Christina**, Monday, March 18, 2013 at 9:57pmz=(1.25-1.35)/(0.25sqrt40)= -0.0791

z=(1.50-1.35)/(0325sqrt40)= 0.0791

but not sure how to read the z scores I dont know if it would be.5000-.5000 or what can someone please help me on the z scores for -0.0791 and 0.0791

- stats. -
**PsyDAG**, Tuesday, March 19, 2013 at 3:01pmSD/√n = .25/6.3246 = .039528192 = .04

Z = (1.25-1.35)/.04 = -.10/.04 = -2.5

Z = (1.50-1.35)/.04 = .15/.04 = ?

Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability of both Z scores between those Z scores and mean. Add the two together.

**Answer this Question**

**Related Questions**

stats. - The mean number of bumped airline passengers per day is 1.35 and the ...

stats. - The mean number of bumped airline passengers per day s 1.35 and the ...

Stats - Among 15,378 Delta airline passengers randomly selected, 3 were bumped ...

statistics - The Ace AirLines has a policy of overbooking flights. The random ...

college stats - help please!!! 1. The average number of bumped passengers per ...

stat - The ministry of transport and communication is responsible for the ...

stats. - The amount that airlines spend on food per passenger is normally ...

Statistics - The number of passengers on the Carnival Sensation during one-week ...

Stats 330- HELP - I need some help on this question it has two parts but i can'...

statistics - In response to the increasing weight of airline passengers, the ...